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HOW TO WRITE AN ESSAY FOR ISC BOARD? HOW TO WRITE AN ISC COMPOSITION?

  HOW TO WRITE AN ESSAY FOR ISC BOARD? HOW TO WRITE AN ISC COMPOSITION?   Description Of A Process   – “ Writing An Essay . ” One of the characteristic features of the human brain that separates us from other species is our creativity and ability to think about various topics. The practically  infinite scope   of our thoughts makes it extremely difficult to streamline them in a single direction for a very long time, something that can only be achieved by   continuous   practice and focus. However, there remains something even more difficult, the ability to reproduce your thoughts coherently on paper.  This seemingly impossible task is what we call “ writing an essay. ”   Essay writing is an extensive process that involves four major steps:   conceiving a topic, structuring the points to write, putting these points in writing, and revisiting for rectifying possible errors.   The difficulty of these steps increases as we proceed from ...

किन्हीं दो विषयों पर टिप्पणी लिखिए:- १. टिप्पण की विशेषताएं २. प्रतिवेदन का महत्व ३. सामान्य हिंदी और कार्यालयी हिंदी ४. व्यावसायिक पत्र के प्रकार | Kinhi Do Vishayon Par Tippan Likhiye

किन्हीं दो विषयों पर टिप्पणी लिखिए:- १. टिप्पण की विशेषताएं  २. प्रतिवेदन का महत्व ३. सामान्य हिंदी और कार्यालयी हिंदी  ४. व्यावसायिक पत्र के प्रकार Kinhi Do Vishayon Par Tippan Likhiye | Hindi Bhasha 'Kha'  तिप्पणी की विशेषताएँ और सुझाव: एक अच्छी टिप्पणी हमेशा सार्थक और संरचित होती है जो पाठकों को समझने में मदद करती है और सही दिशा में मार्गदर्शन करती है। यदि आप एक टिप्पणी लिख रहे हैं, तो इसे ध्यानपूर्वक सोचें और निम्नलिखित विशेषताओं का ध्यान रखें: सटीकता और संवेदनशीलता: आपकी टिप्पणी सटीक और संवेदनशील होनी चाहिए। जिससे पाठक आपकी बातों को सही से समझ सकें। संक्षेप में स्पष्टता: अधिक शब्दों की जगह, संक्षेप में स्पष्ट भाषा का उपयोग करें। सकारात्मक और सहायक: टिप्पणी सकारात्मक होनी चाहिए और पाठकों को कुछ सीखने के लिए प्रेरित करनी चाहिए। विवेचना करें: आपकी टिप्पणी में यदि विवेचना है, तो इसे और बढ़ावा देने के लिए समर्थन दीजिए। सही त्रुटियों को सुधारें: अगर आपने टिप्पणी में किसी त्रुटि को पहचाना है, तो उसे सही करें ताकि पाठकों को सही जानकारी मिले। इन सुझावों...

A Uniform Spring Of Length L Has Force Constant K. The Spring Is Cut Into Two Pieces Of Unstressed Lengths L1, L2 Where (L1/l2)= (N1/n2). Express The Force Constants K1 And K2 Of The Two Pieces In Terms Of K, N1 And N2

Q) A Uniform Spring Of Length L Has Force Constant K. The Spring Is Cut Into Two Pieces Of Unstressed Lengths L1, L2 Where (L1/l2)= (N1/n2). Express The Force Constants K1 And K2 Of The Two Pieces In Terms Of K, N1 And N2. Ans)1)  Relate spring lengths and force constant: The force constant reflects the stiffness of a spring and is inversely proportional to its length.  This means: K ∝ 1 / L 2. Consider the total spring constant: Since the original spring (length L) has force constant K,  the total stored energy within it is KE = ½ K L². 3. Distribute energy after cutting: When the spring is cut into two pieces with lengths L1 and L2,  the total stored energy remains the same.  Therefore: ½ K L² = ½ K₁ L₁² + ½ K₂ L₂² 4. Substitute length ratio: We are given L₁/L₂ = N₁/N₂.  Square both sides and rearrange: L₁² = (N₁²/N₂²) L₂² 5. Substitute and combine equations: Substitute L₁² from step 4 into the energy equation: ½ K L² = ½ K₁ (N₁²/N₂²) L₂² + ½ K₂ L₂² Rearr...

An Alternating Emf Of Peak To Peak Value Of 40 V Is Applied Across The Series Combination Of An Inductor Of Inductance 100mh Capacitor Of Capacitance 1uf And Resistance 100 Ohm . Determine The Bandwidth And Quality Factor.

Q) An Alternating Emf Of Peak To Peak Value Of 40 V Is Applied Across The Series Combination Of An Inductor Of Inductance 100mh Capacitor Of Capacitance 1uf And Resistance 100 Ohm. Determine The Bandwidth And Quality Factor. Ans) METHOD 1:- METHOD 2) 1. Calculate Impedance: First, we need to determine the total impedance (Z) of the circuit at a specific frequency. Each component contributes to the impedance: Inductive reactance (X_L) = 2πfL ,  where f is the frequency. Capacitive reactance (X_C) = 1/(2πfC) . Total impedance (Z) = √(R^2 + (X_L - X_C)^2) . 2. Find Resonant Frequency: At the resonant frequency (f_r), X_L and X_C cancel each other out, leaving only the resistance in the circuit. This results in minimum impedance and maximum current flow. The resonant frequency can be calculated by: f_r = 1/(2π√(LC)). 3. Calculate Bandwidth: The bandwidth (B) represents the range of frequencies around the resonant frequency where the impedance remains close to its minimum value. ...

A Damped Harmonic Oscillator Has The Amplitude Of 20cm. It Reduces To 2cm After 100 Oscillations Each Of The Time Period 4.6s. Calculate Its Logarithmic Damping Constant. Compute The Number Of Oscillations In Which The Amplitude Drops By 50%

Q) A Damped Harmonic Oscillator Has The Amplitude Of 20cm. It Reduces To 2cm After 100 Oscillations Each Of The Time Period 4.6s. Calculate Its Logarithmic Damping Constant. Compute The Number Of Oscillations In Which The Amplitude Drops By 50%. Damped Harmonic Oscillator Calculations Here's how we can calculate the logarithmic damping constant and the number of oscillations for a 50% drop in amplitude for the given damped harmonic oscillator: 1. Logarithmic Damping Constant: The logarithmic damping constant (δ) represents the rate of decay of the amplitude per oscillation. We can calculate it using the formula: δ = (1 / N) * ln(A₀ / A_f) where: N is the number of oscillations (100 in this case) A₀ is the initial amplitude (20 cm) A_f is the final amplitude after N oscillations (2 cm) Plugging in the values, we get: δ = (1 / 100) * ln(20 / 2) ≈ 0.02303 Therefore, the logarithmic damping constant is approximately 0.02303. 2. Number of Oscillations for 50% Drop: We want to find the n...

The Equation Of A Damped Harmonic Oscillation Is Given By 8(d2y/dt2) +24(dx/dt) + 48y =0. Find The Frequency Of The Damped Oscillations.

The Equation Of A Damped Harmonic Oscillation Is Given By :-  8(d2y/dt2) +24(dx/dt) + 48y =0.  Find The Frequency Of The Damped Oscillations  Ans) Method 1:- The Equation Of A Damped Harmonic Oscillation Is Given By 8(d2y/dt2) +24(dx/dt) + 48y =0. Find The Frequency Of The Damped Oscillations. Here's how to find the frequency of the damped oscillations from the given equation: 1.  Identify the coefficients: The coefficient of the second derivative term (8) represents the mass (m). The coefficient of the first derivative term (24) represents the damping coefficient (b). The coefficient of the position term (48) represents the spring constant (k). 2.  Calculate the natural frequency: The natural frequency (ω_0), which is the frequency of the system without damping, is given by: ω_0 = √(k/m) = √(48/8) = √6 ≈ 2.45 rad/s. 3.  Calculate the damping ratio: The damping ratio (ζ), which characterizes the degree of damping, is given by: ζ = b/(2√(mk)) = 24/(2√(8*48))...

A Bug Crawls Towards The Rim With A Constant Speed Vo Along The Spoke Of A Wheel That Is Rotating With Constant Angular Velocity W About A Vertical Axis. Find All Apparent Forces Acting On The Bug. And How Far The Bug Can Crawl Before It Starts To Slip, Given That Coefficient Of Static Friction Between The Bug And The Spoke Is Us.

Q) A Bug Crawls Towards The Rim With A Constant Speed Vo Along The Spoke Of A Wheel That Is Rotating With Constant Angular Velocity W About A Vertical Axis. Find All Apparent Forces Acting On The Bug. And How Far The Bug Can Crawl Before It Starts To Slip, Given That Coefficient Of Static Friction Between The Bug And The Spoke Is Us. Ans)  Apparent Forces Acting on the Bug: There are three apparent forces acting on the bug: Centrifugal Force (Fc) :   This outward force arises due to the bug's circular motion along the rotating wheel. Magnitude: Fc = mv^2/r, where m is the bug's mass, v is its instantaneous velocity relative to the rim (sum of crawling speed and tangential velocity due to wheel rotation), and r is the distance from the bug to the wheel's axis. Direction: Radially outward, away from the wheel's axis. Normal Force (Fn):   This is the force exerted by the spoke on the bug perpendicular to its motion. Magnitude: Fn = N, where N is the reaction force due to t...

A Body Of Mass 1 Kg And Initial Velocity 10 M/s Is Sliding On A Horizontal Surface. If The Coefficient Of Kinetic Friction Between The Body And The Surface Is 0.5. Then Find The Work Done By Friction When The Body Has Transversed A Distance Of 5m Along The Surface.

  Body Of Mass 1 Kg And Initial Velocity 10 m/s Is Sliding On A Horizontal Surface... Q) A Body Of Mass 1 Kg And Initial Velocity 10 m/s Is Sliding On A Horizontal Surface. If The Coefficient Of Kinetic Friction Between The Body And The Surface Is 0.5. Then Find The Work Done By Friction When The Body Has Transversed A Distance Of 5m Along The Surface. Ans)  Calculating the Work Done by Friction Here's how to find the work done by friction when the body transverses 5 meters on the horizontal surface: 1. Calculate the frictional force: First, find the normal force, which is equal to the body's weight since it's on a horizontal surface: Normal force (N) = mass (m) * gravity (g) = 1 kg * 9.81 m/s² = 9.81 N Next, calculate the friction force (F_f) using the kinetic friction coefficient (μ_k): Friction force (F_f) = μ_k * normal force (N) = 0.5 * 9.81 N = 4.905 N 2. Find the work done by friction: Work (W) is the force (F) applied along the direction of displacement (d): Work (W...